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8*2^(x+6)=32

$8 \cdot 2^{x+6}=32$

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Multiply whole numbers

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Q.

8 \cdot 2^{x+6}=32

Simplify the equation: First, let's simplify the equation by dividing both sides by $8$ to isolate the term with the exponent. $\newline$ $8\cdot2^{(x+6)} = 32$ $\newline$ $2^{(x+6)} = \frac{32}{8}$ $\newline$ $2^{(x+6)} = 4$
Express $4$ as power of $2$ : Now, we need to express $4$ as a power of $2$ since the base on the left side is $2$ . $4$ is $2^2$ . So, $2^{x+6} = 2^2$
Set exponents equal: Since the bases are the same, we can set the exponents equal to each other. $x + 6 = 2$
Subtract to solve for $x$ : Subtract $6$ from both sides to solve for $x$ . $x = 2 - 6$ $x = -4$

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