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8+10x^(2)÷(5y) when x=-2 and y=-4?

8+10x2÷(5y) 8+10 x^{2} \div(5 y) when x=−2 x=-2 and y=−4? y=-4 ?

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Full solution

Q. 8+10x2÷(5y) 8+10 x^{2} \div(5 y) when x=−2 x=-2 and y=−4? y=-4 ?
  1. Substitute values into expression: Substitute the given values for xx and yy into the expression.\newlineWe have x=−2x = -2 and y=−4y = -4, so we substitute these values into the expression 8+10x2÷(5y)8 + 10x^{2} \div (5y).
  2. Calculate xx squared: Calculate the value of x2x^{2}.\newlineSince x=−2x = -2, we calculate (−2)2=4(-2)^{2} = 4.
  3. Multiply by 1010: Multiply the result from Step 22 by 1010. We have 10×4=4010 \times 4 = 40.
  4. Calculate 5y5y: Calculate the value of 5y5y.\newlineSince y=−4y = -4, we calculate 5×(−4)=−205 \times (-4) = -20.
  5. Divide results: Divide the result from Step 33 by the result from Step 44.\newlineWe have 40÷(−20)=−240 \div (-20) = -2.
  6. Add to 88: Add the result from Step 55 to 88.\newlineWe have 8+(−2)=68 + (-2) = 6.

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