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7x <= (5x+7)/(3)+2x-3((1)/(2))

$7 x \leqslant \frac{5 x+7}{3}+2 x-3\left(\frac{1}{2}\right)$

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Evaluate rational exponents

Full solution

Q.

7 x \leqslant \frac{5 x+7}{3}+2 x-3\left(\frac{1}{2}\right)

Simplify right side: Step $1$ : Simplify the right side of the inequality. $\newline$ $7x \leq \frac{5x + 7}{3} + 2x - 3 \times \frac{1}{2}$ $\newline$ Combine like terms and simplify the constant: $\newline$ $7x \leq \frac{5x + 7}{3} + 2x - 1.5$
Eliminate fraction: Step $2$ : Eliminate the fraction by multiplying every term by $3$ . $3 \times 7x \leq 3 \times \left(\frac{5x + 7}{3}\right) + 3 \times 2x - 3 \times 1.5$ $21x \leq 5x + 7 + 6x - 4.5$
Combine like terms: Step $3$ : Combine like terms on the right side. $\newline$ $21x \leq 11x + 2.5$
Isolate variable term: Step $4$ : Subtract $11x$ from both sides to isolate the variable term on one side. $\newline$ $21x - 11x \leq 2.5$ $\newline$ $10x \leq 2.5$
Divide to solve for x: Step $5$ : Divide both sides by $10$ to solve for $x$ . $\newline$ $x \leq \frac{2.5}{10}$ $\newline$ $x \leq 0.25$

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