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Solve for a.
7a-4-4a=3(3a+7)+23

Solve for $a$ . $\newline$ $7 a-4-4 a=3(3 a+7)+23$

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Add three or more integers

Full solution

Q. Solve for

a

.

\newline

7 a-4-4 a=3(3 a+7)+23

Simplify left side: First, simplify the left side of the equation by combining like terms. $\newline$ $7a - 4a = 3a$ $\newline$ So the equation becomes: $\newline$ $3a - 4 = 3(3a + 7) + 23$
Distribute on right side: Next, distribute the $3$ on the right side of the equation to both $3a$ and $7$ . $\newline$ $3 \times 3a = 9a$ $\newline$ $3 \times 7 = 21$ $\newline$ So the equation becomes: $\newline$ $3a - 4 = 9a + 21 + 23$
Combine constant terms: Now, combine the constant terms on the right side of the equation. $\newline$ $21 + 23 = 44$ $\newline$ So the equation becomes: $\newline$ $3a - 4 = 9a + 44$
Isolate term with 'a': Next, we want to get all the terms with 'a' on one side and the constants on the other side. Subtract $9a$ from both sides of the equation. $\newline$ $3a - 9a = -6a$ $\newline$ So the equation becomes: $\newline$ $-6a - 4 = 44$
Add to isolate term: Now, add $4$ to both sides of the equation to isolate the term with ' $a$ '. $\newline$ $-6a - 4 + 4 = 44 + 4$ $\newline$ So the equation becomes: $\newline$ $-6a = 48$
Divide to solve for 'a': Finally, divide both sides of the equation by $-6$ to solve for 'a'. $\newline$ $\frac{-6a}{-6} = \frac{48}{-6}$ $\newline$ $a = -8$

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