Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

The need of a vegetable store in apples is 10,000kg10,000 \, \text{kg} per quarter, and apples are consumed evenly and continuously. Apples are ordered once a quarter and delivered in batches of the same volume specified in the order. Storage of one kg of apples in the warehouse costs 20kopecks20 \, \text{kopecks} per day, and delivery of a batch costs 12,000rubles12,000 \, \text{rubles}. Delay in selling apples due to their unavailability is inadmissible. Determine the most economical batch volume and the interval between deliveries to be specified in the order (it is assumed that the supplier does not allow delays in deliveries).

Full solution

Q. The need of a vegetable store in apples is 10,000kg10,000 \, \text{kg} per quarter, and apples are consumed evenly and continuously. Apples are ordered once a quarter and delivered in batches of the same volume specified in the order. Storage of one kg of apples in the warehouse costs 20kopecks20 \, \text{kopecks} per day, and delivery of a batch costs 12,000rubles12,000 \, \text{rubles}. Delay in selling apples due to their unavailability is inadmissible. Determine the most economical batch volume and the interval between deliveries to be specified in the order (it is assumed that the supplier does not allow delays in deliveries).
  1. Define Variables and Problem: Define the variables and the problem.\newlineLet QQ be the batch volume in kilograms, and let TT be the interval between deliveries in days. The store needs 10,00010,000 kg of apples per quarter (9090 days). The cost of storage is 0.200.20 rubles per kg per day, and the delivery cost for each batch is 12,00012,000 rubles.
  2. Calculate Deliveries per Quarter: Calculate the number of deliveries per quarter.\newlineSince the store orders once a quarter and needs 10,00010,000 kg of apples, the number of deliveries per quarter is 10,000/Q10,000 / Q.
  3. Calculate Storage Cost: Calculate the total storage cost per quarter. The average inventory level is Q2\frac{Q}{2}, because the store starts with QQ kg and ends with 00 kg before the next delivery. The storage cost per quarter is (Q2)0.20 rubles/kg/day90 days.\left(\frac{Q}{2}\right) * 0.20 \text{ rubles/kg/day} * 90 \text{ days}.
  4. Calculate Delivery Cost: Calculate the total delivery cost per quarter. The delivery cost per quarter is (10,000/Q)×12,000(10,000 / Q) \times 12,000 rubles, because each batch costs 12,00012,000 rubles and there are 10,000/Q10,000 / Q batches per quarter.
  5. Write Total Cost Function: Write the total cost function.\newlineThe total cost per quarter, C(Q)C(Q), is the sum of the storage cost and the delivery cost. So, C(Q)=(Q2)×0.20×90+(10,000Q)×12,000C(Q) = (\frac{Q}{2}) \times 0.20 \times 90 + (\frac{10,000}{Q}) \times 12,000.
  6. Find Derivative of Cost Function: Find the derivative of the total cost function with respect to QQ. To minimize the total cost, we take the derivative of C(Q)C(Q) with respect to QQ and set it to zero. The derivative is C(Q)=(0.20×90/2)(10,000×12,000/Q2)C'(Q) = (0.20 \times 90 / 2) - (10,000 \times 12,000 / Q^2).
  7. Solve for Q: Solve for Q.\newlineSetting the derivative equal to zero gives us (0.20×90/2)=(10,000×12,000/Q2)(0.20 \times 90 / 2) = (10,000 \times 12,000 / Q^2). Solving for Q, we get Q2=(10,000×12,000)/(0.20×90/2)Q^2 = (10,000 \times 12,000) / (0.20 \times 90 / 2). Let's calculate this.\newlineQ2=(10,000×12,000)/(0.20×90/2)Q^2 = (10,000 \times 12,000) / (0.20 \times 90 / 2)\newlineQ2=(120,000,000)/(9)Q^2 = (120,000,000) / (9)\newlineQ2=13,333,333.33Q^2 = 13,333,333.33\newlineQ=13,333,333.33Q = \sqrt{13,333,333.33}\newlineQ3650Q \approx 3650 kg
  8. Calculate Interval Between Deliveries: Calculate the interval between deliveries, TT. Since the store consumes apples continuously, TT is the time it takes to sell the batch volume QQ. The store needs 10,00010,000 kg per 9090 days, so the daily consumption is 10,000/9010,000 / 90 kg/day. The interval TT is then QQ divided by the daily consumption. T=Q(10,000/90)T = \frac{Q}{(10,000 / 90)} T=3650(10,000/90)T = \frac{3650}{(10,000 / 90)} T=3650(111.11)T = \frac{3650}{(111.11)} T32.85T \approx 32.85 days

More problems from Solve a system of equations using any method: word problems