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7(3y+4)=21 Find y value

$7(3 y+4)=21$ Find $y$ value.

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Solve two-step equations with parentheses

Full solution

Q.

7(3 y+4)=21

Find

y

value.

Distribute terms inside parentheses: Distribute the $7$ to both terms inside the parentheses. $\newline$ We need to apply the distributive property, which states that $a(b + c) = ab + ac$ . $\newline$ So, $7(3y + 4)$ becomes $7\times3y + 7\times4$ . $\newline$ This simplifies to $21y + 28$ .
Set up the equation: Set up the equation with the distributed terms. $\newline$ Now we have the equation $21y + 28 = 21$ .
Subtract to isolate $y$ : Subtract $28$ from both sides of the equation to isolate the term with the variable $y$ . We want to get $y$ by itself on one side of the equation, so we need to remove the constant term from the left side. $21y + 28 - 28 = 21 - 28$ . This simplifies to $21y = -7$ .
Divide to solve for y: Divide both sides of the equation by $21$ to solve for $y$ . $\newline$ To isolate $y$ , we divide both sides by the coefficient of $y$ , which is $21$ . $\newline$ $\frac{21y}{21} = \frac{-7}{21}$ . $\newline$ This simplifies to $y = -\frac{1}{3}$ .

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