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7*(2i+12)=
Your answer should be a complex number in the form 
a+bi where 
a and 
b are real numbers.

7(2i+12)= 7 \cdot(2 i+12)= \newlineYour answer should be a complex number in the form a+bi a+b i where a a and b b are real numbers.

Full solution

Q. 7(2i+12)= 7 \cdot(2 i+12)= \newlineYour answer should be a complex number in the form a+bi a+b i where a a and b b are real numbers.
  1. Distribute multiplication: Distribute the multiplication of 77 to both terms inside the parentheses.\newline7×(2i+12)7 \times (2i + 12) \newline= 7×2i+7×127 \times 2i + 7 \times 12
  2. Perform multiplication: Perform the multiplication for each term.\newline=14i+84= 14i + 84
  3. Write in a+bia+bi form: Write the result in the form a+bia + bi.\newlineThe real part (aa) is 8484, and the imaginary part (bb) is 1414.\newlineSo, the complex number in the form a+bia + bi is 84+14i84 + 14i.

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