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5(6+3r)+7 >= 127

$5(6+3 r)+7 \geq 127$

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Solve advanced linear inequalities

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Q.

5(6+3 r)+7 \geq 127

Distribute and Simplify: First, distribute $5$ into $(6+3r)$ . $\newline$ $5 \times 6 + 5 \times 3r + 7 \geq 127$ . $\newline$ $30 + 15r + 7 \geq 127$ .
Combine Like Terms: Combine like terms on the left side. $\newline$ $30 + 7 + 15r \geq 127$ . $\newline$ $37 + 15r \geq 127$ .
Isolate Variable: Subtract $37$ from both sides to isolate the term with $r$ . $\newline$ $15r \geq 127 - 37.$ $\newline$ $15r \geq 90.$
Solve for r: Divide both sides by $15$ to solve for r. $\newline$ $r \geq \frac{90}{15}$ . $\newline$ $r \geq 6$ .

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