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5(2x+1)=355(2x+1) = 35 Find xx

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Q. 5(2x+1)=355(2x+1) = 35 Find xx
  1. Distribute Terms: Distribute the 55 across the terms inside the parentheses.\newlineWe need to multiply 55 by each term inside the parentheses (2x2x and 11).\newline5×2x=10x5 \times 2x = 10x\newline5×1=55 \times 1 = 5\newlineSo, 5(2x+1)5(2x+1) becomes 10x+510x + 5.
  2. Write New Equation: Write the new equation after distribution.\newlineThe equation after distribution is 10x+5=3510x + 5 = 35.
  3. Subtract 55: Subtract 55 from both sides of the equation to isolate the term with the variable xx.\newline10x+55=35510x + 5 - 5 = 35 - 5\newlineThis simplifies to 10x=3010x = 30.
  4. Divide by 1010: Divide both sides of the equation by 1010 to solve for xx.10x10=3010\frac{10x}{10} = \frac{30}{10}This simplifies to x=3x = 3.

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