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Let’s check out your problem:
4
w
2
+
5
w
−
81
4w^2+5w-81
4
w
2
+
5
w
−
81
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Home
Math Problems
Algebra 2
Factor quadratics
Full solution
Q.
4
w
2
+
5
w
−
81
4w^2+5w-81
4
w
2
+
5
w
−
81
Find Numbers:
First, we need to find two numbers that multiply to
4
×
(
−
81
)
=
−
324
4\times(-81)=-324
4
×
(
−
81
)
=
−
324
and add up to
5
5
5
.
Verify Numbers:
Looking for two such numbers, we find that
36
36
36
and
−
9
-9
−
9
work because
36
×
(
−
9
)
=
−
324
36 \times (-9) = -324
36
×
(
−
9
)
=
−
324
and
36
+
(
−
9
)
=
27
36 + (-9) = 27
36
+
(
−
9
)
=
27
, oops, that's not right, it should be
5
5
5
.
More problems from Factor quadratics
Question
Factor out the greatest common factor. If the greatest common factor is
1
1
1
, just retype the polynomial.
\newline
4
x
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−
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x
2
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−
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\newline
______
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Posted 2 months ago
Question
Factor
x
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x
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completely.
\newline
All factors in your answer should have integer coefficients.
\newline
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Posted 2 months ago
Question
Find the binomial that completes the factorization.
\newline
t
3
+
u
3
=
(
‾
)
(
t
2
−
t
u
+
u
2
)
t^3 + u^3 = (\underline{\hspace{1cm}}) (t^2 - tu + u^2)
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=
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Posted 2 months ago
Question
Factor.
\newline
g
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−
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g
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g
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Posted 2 months ago
Question
Factor.
\newline
2
y
3
−
y
2
+
16
y
−
8
2y^3 - y^2 + 16y - 8
2
y
3
−
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\newline
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\newline
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Posted 2 months ago
Question
Factor.
\newline
2
x
8
+
7
x
2
2x^8 + 7x^2
2
x
8
+
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x
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\newline
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Posted 3 months ago
Question
Factor.
\newline
9
y
12
+
4
y
5
−
y
2
9y^{12} + 4y^5 - y^2
9
y
12
+
4
y
5
−
y
2
\newline
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Posted 3 months ago
Question
Factor.
\newline
6
a
4
+
3
a
3
−
a
+
2
6a^4 + 3a^3 - a + 2
6
a
4
+
3
a
3
−
a
+
2
\newline
_____
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Posted 3 months ago
Question
Factor.
\newline
4
c
7
−
2
c
5
+
c
2
−
5
4c^7 - 2c^5 + c^2 - 5
4
c
7
−
2
c
5
+
c
2
−
5
\newline
_____
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Posted 3 months ago
Question
Factor.
\newline
7
m
9
+
2
m
6
−
m
3
+
4
m
−
10
7m^9 + 2m^6 - m^3 + 4m - 10
7
m
9
+
2
m
6
−
m
3
+
4
m
−
10
\newline
_____
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Posted 3 months ago