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4a+6b=104a+6b=10 2a4b=122a-4b=12 what is 12a12a

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Q. 4a+6b=104a+6b=10 2a4b=122a-4b=12 what is 12a12a
  1. Multiply by 22: First, let's multiply the second equation by 22 to make the coefficient of aa the same in both equations.\newlineSo, 2×(2a4b)=2×122\times(2a - 4b) = 2\times12 gives us 4a8b=244a - 8b = 24.
  2. Subtract to eliminate aa: Now, we subtract the second equation from the first one to eliminate aa.(4a + 6b) - (4a - 8b) = 10 - 24\. This simplifies to \$14b = -14.
  3. Solve for b: Next, we divide both sides by 1414 to solve for b.\newlineb=1414b = \frac{-14}{14}, which simplifies to b=1b = -1.
  4. Substitute bb into equation: Now we'll substitute b=1b = -1 back into one of the original equations to solve for aa. Let's use the first equation: 4a+6(1)=104a + 6(-1) = 10. This simplifies to 4a6=104a - 6 = 10.
  5. Isolate 4a4a term: Add 66 to both sides to isolate the 4a4a term.\newline4a=10+64a = 10 + 6, which simplifies to 4a=164a = 16.
  6. Solve for aa: Now, divide both sides by 44 to solve for aa.a=164a = \frac{16}{4}, which simplifies to a=4a = 4.
  7. Find 12a12a: Finally, we need to find the value of 12a12a. So we multiply the value of aa by 1212. 12a=12×412a = 12 \times 4, which simplifies to 12a=4812a = 48.