Multiply by 2: First, let's multiply the second equation by 2 to make the coefficient of a the same in both equations.So, 2×(2a−4b)=2×12 gives us 4a−8b=24.
Subtract to eliminate a: Now, we subtract the second equation from the first one to eliminate a.(4a + 6b) - (4a - 8b) = 10 - 24\. This simplifies to \$14b = -14.
Solve for b: Next, we divide both sides by 14 to solve for b.b=14−14, which simplifies to b=−1.
Substitute b into equation: Now we'll substitute b=−1 back into one of the original equations to solve for a. Let's use the first equation: 4a+6(−1)=10. This simplifies to 4a−6=10.
Isolate 4a term: Add 6 to both sides to isolate the 4a term.4a=10+6, which simplifies to 4a=16.
Solve for a: Now, divide both sides by 4 to solve for a.a=416, which simplifies to a=4.
Find 12a: Finally, we need to find the value of 12a. So we multiply the value of a by 12. 12a=12×4, which simplifies to 12a=48.
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