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$47 (x^2 \times 11) =7$

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Powers with negative bases

Full solution

Q.

47 (x^2 \times 11) =7

Write Equation Given: First, let's write down the equation as it is given: $47 \times x^2 \times 11 = 7$ .
Simplify Left Side: Now, we need to simplify the left side of the equation by multiplying $47$ and $11$ together. This gives us $47 \times 11 \times x^2$ . $\newline$ $47 \times 11 = 517$ $\newline$ So, the equation now is $517 \times x^2 = 7$ .
Isolate $x^2$ : Next, we need to isolate $x^2$ by dividing both sides of the equation by $517$ . $\newline$ $x^2 = \frac{7}{517}$
Perform Division: Now, we perform the division to find the value of $x^2$ . $\newline$ $x^2 = \frac{7}{517} \approx 0.01354$ (rounded to five decimal places for simplicity)
Find Value of $x^2$ : To find the value of $x$ , we need to take the square root of both sides of the equation. $\newline$ $x = \sqrt{0.01354}$
Calculate Square Root: Calculating the square root gives us the value of $x$ . $x \approx \pm0.11633$ (rounded to five decimal places for simplicity)

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