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45 propare
4. 
(2.5:} points) You are preparing a chloroform 
(CH_(3)Cl) solution in 2-propanol. Calculate the following. Remember to show your work.

Cl_(7)Clln ln ln_(3)H_(8)
a. How many moles of chloroform do are present in 
56.0cg of a pure liquid?
Imoles
b. If the chloroform is dissolved in 2-propanol for a final volume of 
100mL, what is the molar concentration?
c. If the solution is diluted to 
100 muM, what is the final volume of the solution?

4545 propare\newline44. (2.5 \left(2.5\right. points) You are preparing a chloroform (CH3Cl) \left(\mathrm{CH}_{3} \mathrm{Cl}\right) solution in 22-propanol. Calculate the following. Remember to show your work.\newlineCl7Cllnlnln3H8 \mathrm{Cl}_{7} \mathrm{Cl} \ln \ln \mathrm{ln}_{3} \mathrm{H}_{8} \newlinea. How many moles of chloroform do are present in 56.0cg 56.0 \mathrm{cg} of a pure liquid?\newlineImoles\newlineb. If the chloroform is dissolved in 22-propanol for a final volume of 100 mL 100 \mathrm{~mL} , what is the molar concentration?\newlinec. If the solution is diluted to 100μM 100 \mu \mathrm{M} , what is the final volume of the solution?

Full solution

Q. 4545 propare\newline44. (2.5 \left(2.5\right. points) You are preparing a chloroform (CH3Cl) \left(\mathrm{CH}_{3} \mathrm{Cl}\right) solution in 22-propanol. Calculate the following. Remember to show your work.\newlineCl7Cllnlnln3H8 \mathrm{Cl}_{7} \mathrm{Cl} \ln \ln \mathrm{ln}_{3} \mathrm{H}_{8} \newlinea. How many moles of chloroform do are present in 56.0cg 56.0 \mathrm{cg} of a pure liquid?\newlineImoles\newlineb. If the chloroform is dissolved in 22-propanol for a final volume of 100 mL 100 \mathrm{~mL} , what is the molar concentration?\newlinec. If the solution is diluted to 100μM 100 \mu \mathrm{M} , what is the final volume of the solution?
  1. Convert to grams: Step 11: Convert the mass of chloroform from centigrams to grams. 56.0cg=0.56g56.0\,\text{cg} = 0.56\,\text{g}
  2. Calculate moles: Step 22: Calculate the moles of chloroform using its molar mass.\newlineMolar mass of chloroform CHCl3CHCl_3 = 12.0112.01 (C) + 1.011.01 (H) + 3×35.453 \times 35.45 (Cl) = 119.37119.37 g/mol\newlineMoles of chloroform = 0.560.56 g / 119.37119.37 g/mol = 0.004690.00469 moles
  3. Molar concentration: Step 33: Calculate the molar concentration of the solution.\newlineTotal volume = 100mL=0.1L100 \, \text{mL} = 0.1 \, \text{L}\newlineMolar concentration = 0.00469moles0.1L=0.0469M\frac{0.00469 \, \text{moles}}{0.1 \, \text{L}} = 0.0469 \, \text{M}
  4. Calculate final volume: Step 44: Calculate the final volume of the solution when diluted to 100μM100 \mu M.\newline100μM=0.0001M100 \mu M = 0.0001 M\newlineUsing the dilution formula C1V1=C2V2C_1V_1 = C_2V_2, where C1=0.0469MC_1 = 0.0469 M, V1=0.1LV_1 = 0.1 L, C2=0.0001MC_2 = 0.0001 M\newlineV2=(0.0469M×0.1L)/0.0001M=46.9LV_2 = (0.0469 M \times 0.1 L) / 0.0001 M = 46.9 L