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4 Prahsant and Katy each try to work out the answer to 
sqrt(3^(2)+4^(2)). Prashant writes this working.

{:[sqrt(3^(2)+4^(2))],[=sqrt(3^(2))+sqrt(4^(2))],[=sqrt9+sqrt16],[=3+4],[=7]:}
Katy writes this working.

{:[sqrt(3^(2)+4^(2))],[=sqrt(9+16)],[=sqrt25],[=5]:}
Who is correct?

44 Prahsant and Katy each try to work out the answer to 32+42 \sqrt{3^{2}+4^{2}} . Prashant writes this working.\newline32+42=32+42=9+16=3+4=7 \begin{array}{l} \sqrt{3^{2}+4^{2}} \\ =\sqrt{3^{2}}+\sqrt{4^{2}} \\ =\sqrt{9}+\sqrt{16} \\ =3+4 \\ =7 \end{array} \newlineKaty writes this working.\newline32+42=9+16=25=5 \begin{array}{l} \sqrt{3^{2}+4^{2}} \\ =\sqrt{9+16} \\ =\sqrt{25} \\ =5 \end{array} \newlineWho is correct?

Full solution

Q. 44 Prahsant and Katy each try to work out the answer to 32+42 \sqrt{3^{2}+4^{2}} . Prashant writes this working.\newline32+42=32+42=9+16=3+4=7 \begin{array}{l} \sqrt{3^{2}+4^{2}} \\ =\sqrt{3^{2}}+\sqrt{4^{2}} \\ =\sqrt{9}+\sqrt{16} \\ =3+4 \\ =7 \end{array} \newlineKaty writes this working.\newline32+42=9+16=25=5 \begin{array}{l} \sqrt{3^{2}+4^{2}} \\ =\sqrt{9+16} \\ =\sqrt{25} \\ =5 \end{array} \newlineWho is correct?
  1. Write Expression: Prashant's first step is to write the expression 32+42\sqrt{3^{2}+4^{2}}.
  2. Separate Square Roots: Prashant then separates the square root of the sum into the sum of two separate square roots: 32+42\sqrt{3^{2}} + \sqrt{4^{2}}. This is a mistake because the square root of a sum is not equal to the sum of the square roots of the addends.

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