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4(2+3)+5(4-2)

4(2+3)+5(4−2) 4(2+3)+5(4-2)

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Full solution

Q. 4(2+3)+5(4−2) 4(2+3)+5(4-2)
  1. Apply Distributive Property: First, we need to apply the distributive property to both terms in the expression.\newline4(2+3)+5(4−2)=4×2+4×3+5×4−5×24(2+3) + 5(4-2) = 4\times 2 + 4\times 3 + 5\times 4 - 5\times 2
  2. Perform Multiplication: Now, we perform the multiplication for each term.\newline4×2=84 \times 2 = 8\newline4×3=124 \times 3 = 12\newline5×4=205 \times 4 = 20\newline5×2=105 \times 2 = 10\newlineSo, the expression becomes 8+12+20−108 + 12 + 20 - 10.
  3. Add and Subtract Numbers: Next, we add and subtract the numbers in the expression. 8+12+20−10=20+20−108 + 12 + 20 - 10 = 20 + 20 - 10
  4. Combine Remaining Terms: Finally, we combine the remaining terms to find the result. 20+20−10=40−10=3020 + 20 - 10 = 40 - 10 = 30

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