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4(2)/(3)-2(1)/(3)

$4 \frac{2}{3}-2 \frac{1}{3}$

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Multiplication with rational exponents

Full solution

Q.

4 \frac{2}{3}-2 \frac{1}{3}

Understand the problem: Understand the problem. $\newline$ We need to subtract the fraction $2\frac{1}{3}$ from the fraction $4\frac{2}{3}$ .
Convert to improper fractions: Convert the mixed numbers to improper fractions. $\newline$ $4\frac{2}{3}$ can be converted to an improper fraction by multiplying the whole number by the denominator and adding the numerator, then placing the result over the original denominator. $\newline$ $4\frac{2}{3} = \frac{(4\times3 + 2)}{3} = \frac{(12 + 2)}{3} = \frac{14}{3}$ $\newline$ Similarly, for $2\frac{1}{3}$ : $\newline$ $2\frac{1}{3} = \frac{(2\times3 + 1)}{3} = \frac{(6 + 1)}{3} = \frac{7}{3}$
Subtract improper fractions: Subtract the improper fractions. $\newline$ Now we subtract the second fraction from the first: $\newline$ $(\frac{14}{3}) - (\frac{7}{3}) = \frac{14 - 7}{3}$
Perform subtraction: Perform the subtraction. $\newline$ $(14 - 7)/3 = 7/3$
Convert back to mixed number: Convert the improper fraction back to a mixed number if necessary. $\newline$ Since $\frac{7}{3}$ is an improper fraction and can be expressed as a mixed number, we divide $7$ by $3$ . $\newline$ $7 \div 3 = 2$ with a remainder of $1$ . $\newline$ So, $\frac{7}{3}$ as a mixed number is $2\left(\frac{1}{3}\right)$ .

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