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$4$ （ $-2$ ） $2$ + $8$ （ $-2$ ）+ $3$ （ $-2$ ）+ $6$

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Full solution

Q.

4

（

-2

）

2

+

8

（

-2

）+

3

（

-2

）+

6

Calculate square of $-2$ : Calculate the square of $-2$ . $(-2)^2 = 4$
Multiply by square of $-2$ : Multiply $4$ by the square of $-2$ . $4 \times 4 = 16$
Multiply $8$ by $-2$ : Multiply $8$ by $-2$ . $\newline$ $8 \times (-2) = -16$
Multiply $3$ by $-2$ : Multiply $3$ by $-2$ . $\newline$ $3 \times (-2) = -6$
Add all results: Add all the results together along with the $6$ . $16 + (-16) + (-6) + 6$
Combine and simplify: Combine like terms and simplify. $16 - 16 - 6 + 6 = 0$

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