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4
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=
11



x

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6

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=


=


=



-


=
27




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\begin{tabular}{|c|c|c|c|c|}\newline\hline 44 & + & & = = & 1111 \\\newline\hlinex x & & + & & + \\\newline\hline & + & 66 & = = & \\\newline\hline= = & & = = & & = = \\\newline\hline & - & & = = & 2727 \\\newline\hline\newline\end{tabular}\newlineCrossmath: A mind-bending math game that's simple, but fun\newlineInstall app - Math Puzzle Games - Cross Math Sponsored

Full solution

Q. \begin{tabular}{|c|c|c|c|c|}\newline\hline 44 & + & & = = & 1111 \\\newline\hlinex x & & + & & + \\\newline\hline & + & 66 & = = & \\\newline\hline= = & & = = & & = = \\\newline\hline & - & & = = & 2727 \\\newline\hline\newline\end{tabular}\newlineCrossmath: A mind-bending math game that's simple, but fun\newlineInstall app - Math Puzzle Games - Cross Math Sponsored
  1. Calculate s(x)s(x): Calculate s(x)s(x) first, which is 2x+52x + 5.
  2. Plug into r(x)r(x): Now plug s(x)s(x) into r(x)r(x), so r(s(x))=r(2x+5)r(s(x)) = r(2x + 5).
  3. Replace xx in r(x)r(x): Replace xx in r(x)r(x) with 2x+52x + 5, so r(2x+5)=3(2x+5)r(2x + 5) = 3(2x + 5).
  4. Multiply out the brackets: Multiply out the brackets: 3(2x)+3(5)=6x+153(2x) + 3(5) = 6x + 15.
  5. Final result: So, (rs)(x)=6x+15(r \circ s)(x) = 6x + 15.

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