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3x-2y=-1

y=-x+3
Is 
(1,2) a solution of the system?
Choose 1 answer:
(A) Yes
(B) No

3x2y=1 3 x-2 y=-1 \newliney=x+3 y=-x+3 \newlineIs (1,2) (1,2) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No

Full solution

Q. 3x2y=1 3 x-2 y=-1 \newliney=x+3 y=-x+3 \newlineIs (1,2) (1,2) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No
  1. Substitute and check first equation: First, we will substitute the point (1,2)(1,2) into the first equation and check if it holds true. The first equation is 3x2y=13x - 2y = -1. If we substitute x=1x=1 and y=2y=2, we get 3122=13 \cdot 1 - 2 \cdot 2 = -1.
  2. Verify first equation result: After performing the calculation, we find that 34=13 - 4 = -1, which is true. Therefore, the point (1,2)(1,2) satisfies the first equation.
  3. Substitute and check second equation: Next, we will substitute the point (1,2)(1,2) into the second equation and check if it holds true. The second equation is y=x+3y = -x + 3. If we substitute x=1x=1 and y=2y=2, we get 2=1+32 = -1 + 3.
  4. Verify second equation result: After performing the calculation, we find that 2=22 = 2, which is also true. Therefore, the point (1,2)(1,2) satisfies the second equation as well.
  5. Solution to the system of equations: Since the point (1,2)(1,2) satisfies both equations, it is a solution to the system of equations.

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