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Find the values of xx.\newline3x2+4x+6=03x^2+ 4x+6=0

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Q. Find the values of xx.\newline3x2+4x+6=03x^2+ 4x+6=0
  1. Identify Form: Identify the form of the quadratic equation.\newlineEquation given is 3x2+4x+6=03x^2 + 4x + 6 = 0, which is in standard form ax2+bx+c=0ax^2 + bx + c = 0.\newlineHere, a=3a = 3, b=4b = 4, and c=6c = 6.
  2. Calculate Discriminant: Calculate the discriminant to check if factoring is possible.\newlineDiscriminant, Δ=b24ac=(4)2436=1672=56\Delta = b^2 - 4ac = (4)^2 - 4\cdot3\cdot6 = 16 - 72 = -56.\newlineSince Δ\Delta is negative, the quadratic equation does not have real roots and cannot be factored over the real numbers.