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39.42-20.27

$\begin{array}{r}39.42 \\ -20.27 \\ \hline\end{array}$

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Add and subtract decimals

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Q.

\begin{array}{r}39.42 \\ -20.27 \\ \hline\end{array}

Identify numbers: Identify the numbers to be subtracted. $\newline$ We have two decimal numbers, $39.42$ and $20.27$ , and we need to subtract the second number from the first.
Align and subtract: Align the numbers by their decimal points and subtract. $\newline$ We write the numbers one below the other, making sure to align the decimal points: $\newline$ $39.42$ $\newline$ $-$ $20.27$ $\newline$ ________ $\newline$ We subtract each column starting from the rightmost digit.
Subtract hundredths place: Subtract the hundredths place $2 - 7$ . Since $2$ is less than $7$ , we cannot subtract $7$ from $2$ without borrowing. We borrow $1$ from the tenths place ( $4$ becomes $3$ ), turning the $2$ into $12$ . Now we subtract: $2$ $0$ So, we write $2$ $1$ in the hundredths place.
Subtract tenths place: Subtract the tenths place $3 - 2$ . After borrowing, we have $3$ in the tenths place. We subtract: $3 - 2 = 1$ So, we write $1$ in the tenths place.
Subtract ones place: Subtract the ones place ( $9 - 0$ ). $\newline$ There is no need to borrow since $9$ is greater than $0$ . We subtract: $\newline$ $9 - 0 = 9$ $\newline$ So, we write $9$ in the ones place.
Subtract tens place: Subtract the tens place ( $3 - 2$ ). $\newline$ We subtract: $\newline$ $3 - 2 = 1$ $\newline$ So, we write $1$ in the tens place.
Write final result: Write down the final result. $\newline$ After completing the subtraction, we have: $\newline$ $19.15$ $\newline$ This is the final answer.

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