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33+a=12a33+a=12a

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Q. 33+a=12a33+a=12a
  1. Subtract 'a': Subtract 'a' from both sides to get all the 'a' terms on one side.\newline33+a−a=12a−a33 + a - a = 12a - a\newline33=11a33 = 11a
  2. Divide by 1111: Divide both sides by 1111 to solve for 'a'.\newline3311=11a11\frac{33}{11} = \frac{11a}{11}\newline3=a3 = a

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