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305=(20+X)×3305=(20+X)\times 3

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Q. 305=(20+X)×3305=(20+X)\times 3
  1. Understand the equation: Understand the equation.\newlineThe equation given is 305=(20+X)3305 = (20 + X) * 3. This means that three times the sum of 2020 and some number XX equals 305305.
  2. Divide both sides: Divide both sides of the equation by 33 to isolate the sum on one side.\newline305÷3=(20+X)×3÷3305 \div 3 = (20 + X) \times 3 \div 3\newline101.666=20+X101.666\ldots = 20 + X\newlineThis is incorrect because 305305 divided by 33 does not equal 101.666101.666\ldots.