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3(x-2)+2(3-x)=1

3(x2)+2(3x)=1 3(x-2)+2(3-x)=1

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Q. 3(x2)+2(3x)=1 3(x-2)+2(3-x)=1
  1. Distribute numbers to terms: Distribute the numbers outside the parentheses to the terms inside.\newlineCalculate 3(x2)3(x-2) and 2(3x)2(3-x).\newline3(x2)=3×x3×2=3x63(x-2) = 3\times x - 3\times 2 = 3x - 6\newline2(3x)=2×32×x=62x2(3-x) = 2\times 3 - 2\times x = 6 - 2x
  2. Write with distributed terms: Write the equation with the distributed terms.\newlineCombine the results from Step 11 into the equation.\newline3x6+62x=13x - 6 + 6 - 2x = 1
  3. Combine distributed terms: Combine like terms on the left side of the equation.\newlineAdd (3x2x)(3x - 2x) and (6+6)(-6 + 6).\newline3x2x=x3x - 2x = x\newline6+6=0-6 + 6 = 0\newlineSo, x+0=1x + 0 = 1
  4. Combine like terms: Simplify the equation.\newlineSince 6+6-6 + 6 is 00, it cancels out, leaving xx on the left side.\newlinex=1x = 1