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3×9+25÷5×98−24−321÷3−123×2−120−17= ?3\times9+25\div5\times98-24-321\div3 -123\times2-120-17=\,?

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Solve for a variable using properties of multiplicationright chevron icon

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Q. 3×9+25÷5×98−24−321÷3−123×2−120−17= ?3\times9+25\div5\times98-24-321\div3 -123\times2-120-17=\,?
  1. Multiply and Divide: First, let's do the multiplication and division from left to right. 3×9=273\times9 = 27
  2. Divide and Multiply: Now, divide 2525 by 55. \newline25÷5=525 \div 5 = 5
  3. Subtract 2424: Next, multiply the result by 9898.\newline5×98=4905\times98 = 490
  4. Divide by 33: Subtract 2424 from the previous result.\newline490−24=466490-24 = 466
  5. Subtract from 466466: Divide 321321 by 33.\newline321÷3=107321\div3 = 107
  6. Multiply by 22: Subtract the result from 466466.466−107=359466-107 = 359
  7. Subtract from 359359: Multiply 123123 by 22.\newline123×2=246123\times2 = 246
  8. Subtract 120120: Subtract 246246 from 359359.\newline359−246=113359−246 = 113
  9. Subtract 1717: Subtract 120120 from the previous result.\newline113−120=−7113-120 = -7
  10. Subtract 1717: Subtract 120120 from the previous result.\newline113−120=−7113-120 = -7Finally, subtract 1717.\newline−7−17=−24-7-17 = -24

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