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Let’s check out your problem:
3
∗
8
=
3 * 8=
3
∗
8
=
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Math Problems
Grade 6
Multiply whole numbers
Full solution
Q.
3
∗
8
=
3 * 8=
3
∗
8
=
Understand the problem:
Understand the problem.
\newline
We need to calculate
3
3
3
raised to the power of
8
8
8
, which means multiplying
3
3
3
by itself
7
7
7
more times.
Start with the base:
Start with the base number.
\newline
The base number is
3
3
3
.
Multiply by the base:
Multiply the base number by itself.
3
×
3
=
9
3 \times 3 = 9
3
×
3
=
9
(This is
3
3
3
squared or
3
3
3
to the power of
2
2
2
).
Continue multiplying:
Continue multiplying by the base number.
9
9
9
(from the previous step)
×
3
=
27
\times 3 = 27
×
3
=
27
(This is
3
3
3
to the power of
3
3
3
).
Keep multiplying:
Keep multiplying by the base number.
27
×
3
=
81
27 \times 3 = 81
27
×
3
=
81
(This is
3
3
3
to the power of
4
4
4
).
Continue the process:
Continue the process.
\newline
81
×
3
=
243
81 \times 3 = 243
81
×
3
=
243
(This is
3
3
3
to the power of
5
5
5
).
Multiply again:
Multiply again by the base number.
243
×
3
=
729
243 \times 3 = 729
243
×
3
=
729
(This is
3
3
3
to the power of
6
6
6
).
Multiply by the base:
Multiply by the base number again.
729
×
3
=
2187
729 \times 3 = 2187
729
×
3
=
2187
(This is
3
3
3
to the power of
7
7
7
).
Multiply one last time:
Multiply one last time to achieve the
8
th
8^{\text{th}}
8
th
power.
2187
×
3
=
6561
2187 \times 3 = 6561
2187
×
3
=
6561
(This is
3
3
3
to the power of
8
8
8
).
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\newline
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36
=
9 \times 36=
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×
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=
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9
9
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Question
4
⋅
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4 \cdot 8^{b} = 53
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⋅
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\newline
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x
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\newline
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=
∣
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−
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x
∣
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31
=
∣10
−
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x
∣
\newline
Answer:
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=
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=
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\newline
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6
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25 \times 3
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