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3+6×(5+4)÷3-7

56-2(20+12÷4×3-2×2)+10

6+[(16-4)÷(2^(2)+2)]-2

(96÷12)+14 ×(12+8)÷2

$4$ ) $3+6 \times(5+4) \div 3-7$ $\newline$ $5$ ) $56-2(20+12 \div 4 \times 3-2 \times 2)+10$ $\newline$ $6$ ) $6+\left[(16-4) \div\left(2^{2}+2\right)\right]-2$ $\newline$ $7$ ) $(96 \div 12)+14 \times(12+8) \div 2$

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Factor by grouping

Full solution

Q.

4

)

3+6 \times(5+4) \div 3-7

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5

)

56-2(20+12 \div 4 \times 3-2 \times 2)+10

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6

)

6+\left[(16-4) \div\left(2^{2}+2\right)\right]-2

\newline

7

)

(96 \div 12)+14 \times(12+8) \div 2

First problem: Calculate Inside Parentheses: First problem: $3+6\times(5+4)\div3-7$ . Calculate inside the parentheses $(5+4)$ . $5 + 4 = 9$ .
Multiply and Divide: Multiply $6$ by the result from the parentheses. $\newline$ $6 \times 9 = 54$ .
Add and Subtract: Divide the multiplication result by $3$ . $\newline$ $54 \div 3 = 18$ .
Second problem: Calculate Inside Parentheses: Add $3$ to the division result. $\newline$ $3 + 18 = 21$ .
Calculate $2 \times 2$ : Subtract $7$ from the sum. $\newline$ $21 - 7 = 14$ .
Add and Subtract: Second problem: $56-2(20+12\div4\times3-2\times2)+10$ . Calculate inside the parentheses first, starting with division and multiplication. $12 \div 4 = 3$ and $3 \times 3 = 9$ .
Multiply and Subtract: Now, calculate $2 \times 2$ . $\newline$ $2 \times 2 = 4$ .
Third problem: Calculate Inside Brackets: Add and subtract the results inside the parentheses. $20 + 9 - 4 = 25$ .
Calculate Exponent: Multiply $2$ by the result from the parentheses. $\newline$ $2 \times 25 = 50$ .
Add and Divide: Subtract the multiplication result from $56$ and add $10$ . $\newline$ $56 - 50 + 10 = 16.$
Add and Subtract: Third problem: $6+[(16-4)\div(2^{2}+2)]-2$ . Calculate inside the brackets starting with the parentheses. $16 - 4 = 12$ .
Fourth problem: Calculate Inside Parentheses: Calculate the exponent $2^{2}$ . $2^{2} = 4$ .
Multiply and Divide: Add $2$ to the exponent result. $\newline$ $4 + 2 = 6$ .
Divide and Add: Divide the subtraction result by the sum. $12 \div 6 = 2$ .
Add and Final Result: Add the division result to $6$ and subtract $2$ . $6 + 2 - 2 = 6$ .
Add and Final Result: Add the division result to $6$ and subtract $2$ . $\$6 + 2 - 2 = 6$ \).Fourth problem: $(96\div12)+14 \times(12+8)\div2$ . Calculate inside the parentheses first. $96 \div 12 = 8$ and $12 + 8 = 20$ .
Add and Final Result: Add the division result to $6$ and subtract $2$ . $\newline$ $6 + 2 - 2 = 6$ .Fourth problem: $(96\div12)+14 \times(12+8)\div2$ . $\newline$ Calculate inside the parentheses first. $\newline$ $96 \div 12 = 8$ and $12 + 8 = 20$ .Multiply $14$ by the result from the parentheses. $\newline$ $14 \times 20 = 280$ .
Add and Final Result: Add the division result to $6$ and subtract $2$ . $\$6 + 2 - 2 = 6$ \).Fourth problem: $(96\div12)+14 \times(12+8)\div2$ .Calculate inside the parentheses first. $96 \div 12 = 8$ and $12 + 8 = 20$ .Multiply $14$ by the result from the parentheses. $14 \times 20 = 280$ .Divide the multiplication result by $2$ . $280 \div 2 = 140$ .
Add and Final Result: Add the division result to $6$ and subtract $2$ . $\newline$ $6 + 2 - 2 = 6$ .Fourth problem: $(96\div12)+14 \times(12+8)\div2$ . $\newline$ Calculate inside the parentheses first. $\newline$ $96 \div 12 = 8$ and $12 + 8 = 20$ .Multiply $14$ by the result from the parentheses. $\newline$ $14 \times 20 = 280$ .Divide the multiplication result by $2$ . $\newline$ $280 \div 2 = 140$ .Add the division result from the first parentheses to the final result. $\newline$ $2$ $0$ .

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