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3(4i-1)+2(i+3)=9+5(i-3)-9

3(4i−1)+2(i+3)=9+5(i−3)−9 3(4 i-1)+2(i+3)=9+5(i-3)-9

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Full solution

Q. 3(4i−1)+2(i+3)=9+5(i−3)−9 3(4 i-1)+2(i+3)=9+5(i-3)-9
  1. Distribute and Simplify: First, distribute the numbers outside the parentheses on both sides of the equation.\newlineLeft side: 3(4i−1)+2(i+3)=12i−3+2i+63(4i - 1) + 2(i + 3) = 12i - 3 + 2i + 6\newlineRight side: 9+5(i−3)−9=5i−159 + 5(i - 3) - 9 = 5i - 15
  2. Combine Like Terms: Combine like terms on both sides.\newlineLeft side: 12i+2i−3+6=14i+312i + 2i - 3 + 6 = 14i + 3\newlineRight side: 5i−155i - 15
  3. Set Equal: Set the simplified expressions equal to each other.\newline14i+3=5i−1514i + 3 = 5i - 15
  4. Isolate ii Term: Subtract 5i5i from both sides to get all ii terms on one side.\newline14i−5i+3=−1514i - 5i + 3 = -15\newline9i+3=−159i + 3 = -15
  5. Solve for ii: Subtract 33 from both sides to isolate the term with ii.9i=−189i = -18
  6. Solve for ii: Subtract 33 from both sides to isolate the term with ii.9i=−189i = -18Divide both sides by 99 to solve for ii.i=−2i = -2

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