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$\frac{3}{4}=\frac{1}{3}p-1$

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Add and subtract rational numbers

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Q.

\frac{3}{4}=\frac{1}{3}p-1

Isolate term with p: First, let's isolate the term with p on one side of the equation by adding $1$ to both sides. $\newline$ $\frac{3}{4} + 1 = \frac{1}{3}p$
Convert $1$ to fraction: Now, we need to convert $1$ to a fraction with a common denominator with $\frac{3}{4}$ , which is $4$ . $\newline$ $\frac{3}{4} + \frac{4}{4} = \frac{1}{3}p$
Add fractions: Add the fractions on the left side. $\newline$ $(3 + 4)/4 = \frac{1}{3}p$
Simplify fraction: Simplify the fraction. $\frac{7}{4} = \frac{1}{3}p$
Multiply by reciprocal: To solve for $p$ , we multiply both sides by the reciprocal of $\frac{1}{3}$ , which is $3$ . $\frac{7}{4} \times 3 = p$
Multiply by $3$ : Now, multiply $\frac{7}{4}$ by $3$ . $\newline$ $\frac{7}{4} \times 3 = \frac{21}{4}$

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