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Let’s check out your problem:

3(1)/(6)-1(5)/(9)=

99) 316−159= 3 \frac{1}{6}-1 \frac{5}{9}=

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Full solution

Q. 99) 316−159= 3 \frac{1}{6}-1 \frac{5}{9}=
  1. Convert to Improper Fraction: Now, convert 3(16)3\left(\frac{1}{6}\right) to an improper fraction with the common denominator: (3×6+1)/6=196(3 \times 6 + 1) / 6 = \frac{19}{6}. Then, convert to a fraction with denominator 1818: (19×3)/(6×3)=5718(19 \times 3) / (6 \times 3) = \frac{57}{18}.
  2. Convert to Common Denominator: Next, convert 1(5)9\frac{1(5)}{9} to an improper fraction with the common denominator: (1×9+5)/9=149(1 \times 9 + 5) / 9 = \frac{14}{9}. Then, convert to a fraction with denominator 1818: (14×2)/(9×2)=2818(14 \times 2) / (9 \times 2) = \frac{28}{18}.
  3. Subtract Fractions: Now subtract the two fractions: 5718−2818\frac{57}{18} - \frac{28}{18}.
  4. Perform Subtraction: Perform the subtraction: 57−28=2957 - 28 = 29. So, 5718−2818=2918\frac{57}{18} - \frac{28}{18} = \frac{29}{18}.
  5. Simplify Final Fraction: Finally, simplify the fraction 2918\frac{29}{18} if possible. It can't be simplified further, so the final answer is 2918\frac{29}{18}.

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