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2x+y=4

y=3x-1
Is 
(1,2) a solution to both equations?
Choose 1 answer:
(A) Yes
(B) No

2x+y=4 2 x+y=4 \newliney=3x1 y=3 x-1 \newlineIs (1,2) (1,2) a solution to both equations?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No

Full solution

Q. 2x+y=4 2 x+y=4 \newliney=3x1 y=3 x-1 \newlineIs (1,2) (1,2) a solution to both equations?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No
  1. Substitute and Check First Equation: First, we will substitute the point (1,2)(1,2) into the first equation and check if it holds true. The first equation is 2x+y=42x + y = 4. If we substitute x=1x=1 and y=2y=2, we get 21+2=42 \cdot 1 + 2 = 4.
  2. Verify First Equation: After performing the calculation, we find that 2+2=42 + 2 = 4, which is true. Therefore, the point (1,2)(1,2) satisfies the first equation.
  3. Substitute and Check Second Equation: Next, we will substitute the point (1,2)(1,2) into the second equation and check if it holds true. The second equation is y=3x1y = 3x - 1. If we substitute x=1x=1 and y=2y=2, we get 2=3×112 = 3 \times 1 - 1.
  4. Verify Second Equation: After performing the calculation, we find that 2=312 = 3 - 1, which is also true. Therefore, the point (1,2)(1,2) satisfies the second equation as well.
  5. Solution to the System of Equations: Since the point (1,2)(1,2) satisfies both equations, it is a solution to the system of equations.

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