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$2x + 3y > 12$

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Solve two-step linear inequalities

Full solution

Q.

2x + 3y > 12

Isolate $3y$ term: Isolate the $3y$ term by subtracting $2x$ from both sides. $\newline$ $2x + 3y - 2x > 12 - 2x$ $\newline$ $3y > 12 - 2x$
Divide both sides: Divide both sides by $3$ to solve for $y$ . $\newline$ $\frac{3y}{3} > \frac{12 - 2x}{3}$ $\newline$ $y > 4 - \frac{2}{3}x$

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