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2x+3y=100,5y25=52x+3y=100, 5y-25=5

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Q. 2x+3y=100,5y25=52x+3y=100, 5y-25=5
  1. Identify Equations: Identify the system of equations to solve.\newlineWe have two equations: 2x+3y=1002x + 3y = 100 and 5y25=55y - 25 = 5.\newlineWe will solve this system using the substitution or elimination method.
  2. Solve Second Equation: Solve the second equation for yy.
    5y25=55y - 25 = 5
    Add 2525 to both sides: 5y=5+255y = 5 + 25
    Divide both sides by 55: y=30/5y = 30 / 5
    Simplify: y=6y = 6
  3. Substitute and Calculate: Substitute y=6y = 6 into the first equation.2x+3(6)=1002x + 3(6) = 100 Calculate: 2x+18=1002x + 18 = 100 Subtract 1818 from both sides: 2x=100182x = 100 - 18 Simplify: 2x=822x = 82
  4. Solve for x: Solve for x.\newlineDivide both sides by 22: x=822x = \frac{82}{2}\newlineSimplify: x=41x = 41
  5. Check Solution: Check the solution in both original equations.\newlineFirst equation: 2(41)+3(6)=1002(41) + 3(6) = 100\newlineCalculate: 82+18=10082 + 18 = 100\newlineVerify: 100=100100 = 100

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