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Solve the system of equations : \newline2x+3y=102x+3y=10. \newline4x+7y=214x+7y=21

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Q. Solve the system of equations : \newline2x+3y=102x+3y=10. \newline4x+7y=214x+7y=21
  1. Write Equations: Write down the system of equations.\newlineWe have the following system of linear equations:\newline2x+3y=102x + 3y = 10\newline4x+7y=214x + 7y = 21
  2. Multiply First Equation: Multiply the first equation by 22 to prepare for elimination.\newlineMultiplying the first equation by 22 gives us:\newline4x+6y=204x + 6y = 20\newlineNow we have:\newline4x+6y=204x + 6y = 20\newline4x+7y=214x + 7y = 21
  3. Subtract Equations: Subtract the second equation from the first to eliminate xx.\newline(4x+6y)(4x+7y)=2021(4x + 6y) - (4x + 7y) = 20 - 21\newlineThis simplifies to:\newline4x+6y4x7y=14x + 6y - 4x - 7y = -1\newlineWhich further simplifies to:\newliney=1-y = -1
  4. Solve for y: Solve for y.\newlineDivide both sides by 1-1 to get:\newliney=1y = 1
  5. Substitute and Solve: Substitute y=1y = 1 into the first original equation to solve for xx. Using the first equation 2x+3y=102x + 3y = 10, we substitute yy with 11: 2x+3(1)=102x + 3(1) = 10 2x+3=102x + 3 = 10
  6. Final Solution: Solve for xx.\newlineSubtract 33 from both sides to isolate 2x2x:\newline2x=1032x = 10 - 3\newline2x=72x = 7\newlineDivide both sides by 22 to get:\newlinex=72x = \frac{7}{2}\newlinex=3.5x = 3.5