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Let’s check out your problem:
2
x
+
16
=
a
(
x
+
8
)
2x+16=a(x+8)
2
x
+
16
=
a
(
x
+
8
)
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Home
Math Problems
Algebra 1
Solve linear equations: mixed review
Full solution
Q.
2
x
+
16
=
a
(
x
+
8
)
2x+16=a(x+8)
2
x
+
16
=
a
(
x
+
8
)
Move Terms, Constants:
Now, let's move all terms with
x
x
x
to one side and constants to the other side.
\newline
Subtract
a
x
ax
a
x
from both sides.
\newline
2
x
−
a
x
+
16
=
8
a
2x - ax + 16 = 8a
2
x
−
a
x
+
16
=
8
a
Subtract
16
16
16
, Isolate x:
Next, subtract
16
16
16
from both sides to isolate the x terms.
\newline
2
x
−
a
x
=
8
a
−
16
2x - ax = 8a - 16
2
x
−
a
x
=
8
a
−
16
Combine Like Terms:
Combine like terms by factoring out
x
x
x
.
\newline
x
(
2
−
a
)
=
8
a
−
16
x(2 - a) = 8a - 16
x
(
2
−
a
)
=
8
a
−
16
Divide to Solve for
x
x
x
:
Finally, divide both sides by
(
2
−
a
)
(2 - a)
(
2
−
a
)
to solve for
x
x
x
.
x
=
8
a
−
16
2
−
a
x = \frac{8a - 16}{2 - a}
x
=
2
−
a
8
a
−
16
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Question
Evaluate.
\newline
6
7
÷
1
6
=
\frac{6}{7} \div \frac{1}{6}=
7
6
÷
6
1
=
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\newline
y
+
3
=
−
4
(
x
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)
y+3=-4(x+7)
y
+
3
=
−
4
(
x
+
7
)
\newline
Choose
1
1
1
answer:
\newline
(A)
−
4
-4
−
4
\newline
(B)
−
7
-7
−
7
\newline
(C)
3
7
\frac{3}{7}
7
3
\newline
(D)
−
3
4
-\frac{3}{4}
−
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Which equation has a constant of proportionality equal to
9
9
9
?
\newline
Choose
1
1
1
answer:
\newline
(A)
y
=
81
3
x
y=\frac{81}{3} x
y
=
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81
x
\newline
(B)
y
=
9
x
y=9 x
y
=
9
x
\newline
(C)
y
=
3
x
y=3 x
y
=
3
x
\newline
(D)
y
=
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9
x
y=\frac{1}{9} x
y
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Solve for
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h
h
.
\newline
3
7
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h
14
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7
\frac{3}{7}=\frac{h}{14}-\frac{2}{7}
7
3
=
14
h
−
7
2
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Solve for
x
x
x
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\newline
−
4.5
=
−
0.5
(
x
−
7.1
)
-4.5=-0.5(x-7.1)
−
4.5
=
−
0.5
(
x
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7.1
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Solve for
n
n
n
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\newline
n
5
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5
n
+
0.6
=
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Solve for
j
j
j
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\newline
−
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3
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4
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3
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−
3
1
=
4
j
−
3
10
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Question
Solve for
m
m
m
.
\newline
m
9
+
2
3
=
7
3
\frac{m}{9}+\frac{2}{3}=\frac{7}{3}
9
m
+
3
2
=
3
7
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Question
Solve for
r
r
r
.
\newline
0.5
(
r
+
2.75
)
=
3
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(
r
+
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)
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y
y
y
.
\newline
−
3
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7
(
y
−
9
7
)
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−
3
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