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Let’s check out your problem:

2pi//1+(e^(-J))/(2)=

2π/1+e−J2= 2 \pi / 1+\frac{e^{-J}}{2}=

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Csc, sec, and cot of special anglesright chevron icon

Full solution

Q. 2π/1+e−J2= 2 \pi / 1+\frac{e^{-J}}{2}=
  1. Simplify expression: First, let's simplify the expression 2π/1+(e−j)/22\pi / 1 + (e^{-j}) / 2. The double slash seems to be a typo, so we'll assume it's meant to be a single slash, indicating division.
  2. Rewrite expression: Now, we'll simplify 2π1+e−j2\frac{2\pi}{1} + \frac{e^{-j}}{2}. Since 2π1\frac{2\pi}{1} is just 2π2\pi, we can rewrite the expression as 2π+e−j22\pi + \frac{e^{-j}}{2}.
  3. Simplify complex number: Next, we need to simplify (e(−j))/2(e^{(-j)})/2. However, since e(−j)e^{(-j)} is a complex number (Euler's formula), and we're not given any further instructions on how to handle complex numbers, we'll leave it as is.
  4. Final simplified form: So, the simplified form of the expression is 2π+(e−j2)2\pi + \left(\frac{e^{-j}}{2}\right). There's no further simplification we can do without additional context or instructions.

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