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2log3(x+5)=42\log_{3}(x+5)=4

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Q. 2log3(x+5)=42\log_{3}(x+5)=4
  1. Isolate log term: Calculate the value of the logarithmic expression by dividing both sides by 22 to isolate the log term.2log3(x+5)2=42\frac{2\log_3(x+5)}{2} = \frac{4}{2}log3(x+5)=2\log_3(x+5) = 2
  2. Convert to exponential form: Convert the logarithmic equation to its exponential form.\newline3log3(x+5)=323^{\log_3(x+5)} = 3^2
  3. Simplify exponential equation: Simplify the exponential equation. x+5=32x+5 = 3^2 x+5=9x+5 = 9
  4. Solve for x: Solve for x by subtracting 55 from both sides.\newlinex=95x = 9 - 5\newlinex=4x = 4

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