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$\frac{2(x+1)}{3} = 1$

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Solve equations with the distributive property

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Q.

\frac{2(x+1)}{3} = 1

Eliminate denominator by multiplication: Multiply both sides of the equation by $3$ to eliminate the denominator. $\newline$ $\frac{2(x + 1)}{3} \times 3 = 1 \times 3$ $\newline$ $2(x + 1) = 3$
Solve for $x + 1$ : Divide both sides of the equation by $2$ to solve for the term $(x + 1)$ . $\frac{2(x + 1)}{2} = \frac{3}{2}$ $(x + 1) = \frac{3}{2}$
Subtract $1$ to solve for x: Subtract $1$ from both sides of the equation to solve for x. $\newline$ $(x + 1) - 1 = \frac{3}{2} - 1$ $\newline$ $x = \frac{3}{2} - \frac{2}{2}$
Combine fractions: Combine the fractions on the right side of the equation. $\newline$ $x = \frac{3 - 2}{2}$ $\newline$ $x = \frac{1}{2}$

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