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$2$.) A life insurance company examined the medical records of $1,005$ women who died in $2010$ and discovered that $300$ of the women died from causes related to cancer. Moreover, $473$ of the $1,005$ women had at least one parent who suffered from cancer, and, of these $473$ women, $225$ died from causes related to cancer.$\newline$Let $\newline$$P(A)$ be the probability that a given woman from the total group died of cancer, and let $\newline$$P(A\mid B)$ be the probability that a given woman died of cancer, given that she had at least one parent who suffered from cancer. Calculate $\newline$$\frac{P(A\mid B)}{P(A)}$.$\newline$(A) $0.627$$\newline$(B) $300$$0$$\newline$(C) $300$$1$$\newline$(D) $300$$2$$\newline$(E) $300$$3$