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$2(3x+1)=5(2x-3)$

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Solve linear inequalities

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Q.

2(3x+1)=5(2x-3)

Distribute terms: Distribute the $2$ into $(3x+1)$ and the $5$ into $(2x-3)$ . $\newline$ $2(3x) + 2(1) = 5(2x) - 5(3)$ $\newline$ $6x + 2 = 10x - 15$
Move $x$ terms: Move all $x$ terms to one side by subtracting $6x$ from both sides. $\newline$ $6x + 2 - 6x = 10x - 15 - 6x$ $\newline$ $2 = 4x - 15$
Add $15$ : Add $15$ to both sides to isolate the $x$ term. $\newline$ $2 + 15 = 4x - 15 + 15$ $\newline$ $17 = 4x$
Divide by $4$ : Divide both sides by $4$ to solve for $x$ . $\frac{17}{4} = \frac{4x}{4}$ $x = \frac{17}{4}$

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