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2(3c-2)=c+2(2c+4)

2(3c−2)=c+2(2c+4) 2(3 c-2)=c+2(2 c+4)

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Full solution

Q. 2(3c−2)=c+2(2c+4) 2(3 c-2)=c+2(2 c+4)
  1. Distribute 22 on left side: Distribute the 22 on the left side of the equation.2(3c−2)=6c−42(3c - 2) = 6c - 4
  2. Distribute 22 on right side: Distribute the 22 on the right side of the equation.c+2(2c+4)=c+4c+8c + 2(2c + 4) = c + 4c + 8
  3. Simplify right side: Simplify the right side of the equation. c+4c+8=5c+8c + 4c + 8 = 5c + 8
  4. Set equal simplified forms: Set the simplified forms of both sides equal to each other. 6c−4=5c+86c - 4 = 5c + 8
  5. Subtract to isolate c term: Subtract 5c5c from both sides to isolate the cc term on one side.\newline6c−5c−4=5c−5c+86c - 5c - 4 = 5c - 5c + 8\newline1c−4=81c - 4 = 8
  6. Add to solve for c: Add 44 to both sides to solve for c.\newlinec−4+4=8+4c - 4 + 4 = 8 + 4\newlinec=12c = 12

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