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Let’s check out your problem:

17*x^(2)+5=(9)/(2)x

17⋅x2+5=92x 17 \cdot x^{2}+5=\frac{9}{2} x

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Full solution

Q. 17⋅x2+5=92x 17 \cdot x^{2}+5=\frac{9}{2} x
  1. Move Terms to One Side: Move all terms to one side of the equation to set it equal to zero.\newline17x2+5−92x=017x^{2} + 5 - \frac{9}{2}x = 0
  2. Clear Fraction: Multiply through by 22 to clear the fraction.\newline2(17x2+5)−9x=02(17x^{2} + 5) - 9x = 0\newline34x2+10−9x=034x^{2} + 10 - 9x = 0
  3. Rearrange Terms: Rearrange the terms in descending order of powers of xx.34x2−9x+10=034x^{2} - 9x + 10 = 0
  4. Factor or Use Formula: Factor the quadratic equation if possible.\newlineBut this quadratic doesn't factor nicely, so we'll use the quadratic formula instead.\newlinex=−(−9)±(−9)2−4⋅34⋅102⋅34x = \frac{-(-9) \pm \sqrt{(-9)^2 - 4 \cdot 34 \cdot 10}}{2 \cdot 34}
  5. Simplify Square Root: Simplify inside the square root and the constants outside. x=[9±81−1360]68x = \frac{[9 \pm \sqrt{81 - 1360}]}{68}
  6. Calculate Discriminant: Calculate the discriminant (inside the square root). 81−1360=−1279\sqrt{81 - 1360} = \sqrt{-1279} Here we hit a snag; the discriminant is negative, which means there are no real solutions to this equation.

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