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15000(1+(0.0325)/(12))^(12*20)

15000(1+0.032512)1220 15000\left(1+\frac{0.0325}{12}\right)^{12 \cdot 20}

Full solution

Q. 15000(1+0.032512)1220 15000\left(1+\frac{0.0325}{12}\right)^{12 \cdot 20}
  1. Identify Formula: Identify the formula for compound interest which is A=P(1+r/n)(nt)A = P(1 + r/n)^{(nt)}, where PP is the principal amount, rr is the annual interest rate, nn is the number of times interest is compounded per year, and tt is the time in years.
  2. Plug Values: Plug in the values: P=15000P = 15000, r=0.0325r = 0.0325, n=12n = 12, and t=20t = 20 into the formula.
  3. Calculate Rate per Period: Calculate the rate per period by dividing the annual rate by the number of periods per year: (0.0325)/(12)(0.0325)/(12).
  4. Calculate Base of Exponent: Calculate (1+(0.0325)/(12))(1 + (0.0325)/(12)) to find the base of the exponent.
  5. Raise to Power: Raise the base to the power of the total number of compounding periods: 12×2012\times 20.
  6. Multiply Principal: Multiply the principal amount by the result from the previous step to find the final value.
  7. Perform Calculations: Perform the calculations: 15000(1+0.032512)12×20.15000\left(1+\frac{0.0325}{12}\right)^{12\times 20}.