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15 i*(-i-1)=
Your answer should be a complex number in the form
a+bi where
a and
b are real numbers.

$15 i \cdot(-i-1)=$ $\newline$ Your answer should be a complex number in the form $a+b i$ where $a$ and $b$ are real numbers.

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Write equations of cosine functions using properties

Full solution

Q.

15 i \cdot(-i-1)=

\newline

Your answer should be a complex number in the form

a+b i

where

a

and

b

are real numbers.

Multiply complex numbers: Multiply the complex numbers $15i$ and $(-i - 1)$ . We distribute $15i$ across the terms in the parentheses. $15i \times (-i) + 15i \times (-1)$
Distribute $15i$ : Calculate the product of $15i$ and $-i$ . $\newline$ The product of $i$ and $-i$ is $-i^2$ . Since $i^2 = -1$ , $-i^2 = 1$ . $\newline$ $15i \cdot (-i) = 15 \cdot 1 = 15$
Calculate product of $15i$ and $-i$ : Calculate the product of $15i$ and $-1$ . $\newline$ The product of $i$ and $-1$ is $-i$ . $\newline$ $15i \times (-1) = -15i$
Calculate product of $15i$ and $-1$ : Combine the results from Step $2$ and Step $3$ . $\newline$ $15$ (from Step $2$ ) + ( $-15i$ ) (from Step $3$ )
Combine results from Step $2$ and Step $3$ : Write the final answer in the form $a+bi$ . $\newline$ The real part $a$ is $15$ , and the imaginary part $b$ is $-15$ . $\newline$ So, the final answer is $15 - 15i$ .

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