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15(3)/(4)-10(1)/(2)=

$15 \frac{3}{4}-10 \frac{1}{2}=$

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Powers with negative bases

Full solution

Q.

15 \frac{3}{4}-10 \frac{1}{2}=

Simplify $15(3)/(4)$ : First, let's simplify $15(3)/(4)$ . This means $15$ times $3$ divided by $4$ . $\newline$ $15 \times 3 = 45$ , so we have $45/4$ .
Simplify $10(1)/(2)$ : Now, let's simplify $10(1)/(2)$ . This means $10$ times $1$ divided by $2$ . $\newline$ $10 \times 1 = 10$ , so we have $10/2$ .
Simplify $\frac{10}{2}$ : Simplify $\frac{10}{2}$ . $\newline$ $10$ divided by $2$ is $5$ .
Subtract $\frac{45}{4} - 5$ : Now we have to subtract the two results: $\frac{45}{4} - 5$ . To subtract these, we need a common denominator. Since $5$ is the same as $\frac{20}{4}$ , we can use $4$ as the common denominator.
Subtract $\frac{45}{4} - \frac{20}{4}$ : Subtract $\frac{20}{4}$ from $\frac{45}{4}$ . $\frac{45}{4} - \frac{20}{4} = \frac{(45 - 20)}{4}$ .
Simplify $(45 - 20)/4$ : Simplify $(45 - 20)/4$ . $\frac{25}{4}$ is the result.
Convert $\frac{25}{4}$ to a mixed number: Convert $\frac{25}{4}$ to a mixed number. $\newline$ $25$ divided by $4$ is $6$ with a remainder of $1$ . $\newline$ So, $\frac{25}{4}$ is $6 \frac{1}{4}$ .

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