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Let’s check out your problem:
15
−
2
(
5
−
2
)
=
15-2(5-2)=
15
−
2
(
5
−
2
)
=
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Math Problems
Algebra 2
Evaluate logarithms using a calculator
Full solution
Q.
15
−
2
(
5
−
2
)
=
15-2(5-2)=
15
−
2
(
5
−
2
)
=
Perform Operation Inside Parentheses:
First, we need to perform the operation inside the parentheses.
\newline
Calculate
5
−
2
5 - 2
5
−
2
.
\newline
5
−
2
=
3
5 - 2 = 3
5
−
2
=
3
Multiply Result by
2
2
2
:
Now, we multiply the result by
2
2
2
, as indicated by the expression
2
(
5
−
2
)
2(5-2)
2
(
5
−
2
)
. Multiply
2
2
2
by
3
3
3
.
2
×
3
=
6
2 \times 3 = 6
2
×
3
=
6
Subtract Result from
15
15
15
:
Finally, we subtract the result from
15
15
15
.
\newline
Subtract
6
6
6
from
15
15
15
.
\newline
15
−
6
=
9
15 - 6 = 9
15
−
6
=
9
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Write the exponential equation in logarithmic form.
\newline
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9^3 = 729
9
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\newline
log
□
729
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\log_\square 729 = 3
lo
g
□
729
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e
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e
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ln
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\newline
log
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100
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\newline
log
3
33
=
\log_3 33 =
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g
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\newline
log
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Question
Which property of logarithms does this equation demonstrate?
\newline
log
3
3
+
log
3
6
=
log
3
18
\log_3 3 + \log_3 6 = \log_3 18
lo
g
3
3
+
lo
g
3
6
=
lo
g
3
18
\newline
Choices:
\newline
(A)
Product Property
\text{Product Property}
Product Property
\newline
(B)
Power Property
\text{Power Property}
Power Property
\newline
(C)
Quotient Property
\text{Quotient Property}
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Expand the logarithm. Assume all expressions exist and are well-defined.
\newline
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\newline
log
(
u
v
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\log(uv)
lo
g
(
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)
\newline
_____
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Question
Expand the logarithm. Assume all expressions exist and are well-defined.
\newline
Write your answer as a sum or difference of common logarithms or multiples of common logarithms. The inside of each logarithm must be a distinct constant or variable.
\newline
log
v
7
\log v^7
lo
g
v
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\newline
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Expand the logarithm. Assume all expressions exist and are well-defined.
\newline
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6
6
6
logarithms or multiples of base-
6
6
6
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\newline
log
6
w
6
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