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$13+\frac{6}{y}$ when $y=6$

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Solve two-step linear inequalities

Full solution

Q.

13+\frac{6}{y}

when

y=6

Plug in value of y: First, let's plug in the value of $y$ into the expression. $13 + \frac{6}{y}$ becomes $13 + \frac{6}{6}$
Simplify fraction: Now, let's simplify the fraction $\frac{6}{6}$ . $\frac{6}{6}$ is equal to $1$
Add to $13$ : Next, add the simplified fraction to $13$ . $13 + 1$ equals $14$

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