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13+4x=2(11x+20)+x13 + 4x = 2(11x + 20) + x

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Full solution

Q. 13+4x=2(11x+20)+x13 + 4x = 2(11x + 20) + x
  1. Expand equation: Expand the right side of the equation.\newline13+4x=2(11x+20)+x13 + 4x = 2(11x + 20) + x\newline13+4x=22x+40+x13 + 4x = 22x + 40 + x
  2. Combine like terms: Combine like terms on the right side.\newline13+4x=22x+40+x13 + 4x = 22x + 40 + x\newline13+4x=23x+4013 + 4x = 23x + 40
  3. Subtract to isolate xx: Subtract 4x4x from both sides to get all xx terms on one side.\newline13+4x−4x=23x+40−4x13 + 4x - 4x = 23x + 40 - 4x\newline13=19x+4013 = 19x + 40
  4. Isolate x term: Subtract 4040 from both sides to isolate the x term.\newline13−40=19x+40−4013 - 40 = 19x + 40 - 40\newline−27=19x-27 = 19x
  5. Divide to solve xx: Divide both sides by 1919 to solve for xx.\newline−27/19=19x/19-27 / 19 = 19x / 19\newlinex=−27/19x = -27 / 19

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