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12*(-3i-4)=
Your answer should be a complex number in the form
a+bi where
a and
b are real numbers.

$12 \cdot(-3 i-4)=$ $\newline$ Your answer should be a complex number in the form $a+b i$ where $a$ and $b$ are real numbers.

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Write equations of cosine functions using properties

Full solution

Q.

12 \cdot(-3 i-4)=

\newline

Your answer should be a complex number in the form

a+b i

where

a

and

b

are real numbers.

Multiply real part by $12$ : Multiply the real part of the complex number by $12$ . $\newline$ We have the real part of the complex number as -4＂). Multiplying this by 12 gives us:\(\newline\$12 \times (-4) = -48\)
Multiply imaginary part by \(12\): Multiply the imaginary part of the complex number by \(12\).\(\newline\)The imaginary part of the complex number is \(\(-3\)i＂). Multiplying this by \(12\) gives us:\(\newline\)\(\(12\) \times (\(-3\)i) = \(-36\)i＂)
Combine results for final answer: Combine the results from Step \(1\) and Step \(2\) to get the final answer.\(\newline\)The real part from Step \(1\) is \(-48\) and the imaginary part from Step \(2\) is \(-36i\). Combining these, we get:\(\newline\)\(-48 - 36i\)\(\newline\)This is the final answer in the form \(a + bi\), where \(a\) is the real part and \(b\) is the coefficient of the imaginary part.

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