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11x2198x12011x^2-198x-120

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Q. 11x2198x12011x^2-198x-120
  1. Identify Quadratic Trinomial: Identify the quadratic trinomial and check if there is a common factor for all terms.\newline11x2198x12011x^2-198x-120\newlineCheck for common factors:\newlineGCD(1111, 198198, 120120) = 1111
  2. Factor Out GCD: Factor out the greatest common divisor (GCD) from the quadratic trinomial. 11(x218x11)11(x^2-18x-11)
  3. Find Two Numbers: Now, we need to factor the quadratic expression inside the parentheses. Look for two numbers that multiply to 11-11 (the product of the coefficient of x2x^2 and the constant term) and add up to 18-18 (the coefficient of xx).\newlineThe numbers that satisfy these conditions are 22-22 and +1+1.
  4. Rewrite Middle Term: Rewrite the middle term 18x-18x using the two numbers found in the previous step.\newline11(x222x+x11)11(x^2-22x+x-11)
  5. Group and Factor: Group the terms in pairs and factor by grouping. \newline11((x222x)+(x11))11((x^2-22x)+(x-11))
  6. Factor Common Factors: Factor out the common factors from each group. 11(x(x22)+1(x11))11(x(x-22)+1(x-11))
  7. Re-evaluate Factors: Notice that (x22)(x-22) and (x11)(x-11) are not common factors, and we cannot factor further. This indicates a mistake was made in the previous steps because the quadratic should be factorable. We need to re-evaluate the factors of 11-11 that add up to 18-18.